64x^2-116x+30=0

Solution for 64x^2-116x+30=0 equation:

64x^2-116x+30=0

a = 64; b = -116; c = +30;
Δ = b2-4ac
Δ = -1162-4·64·30
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-76}{2*64}=\frac{40}{128}
=5/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+76}{2*64}=\frac{192}{128}
=1+1/2
$